The Position Of An Object Is Given By X = At3 - Bt2 + Ct, Where A = 4.1 M/S^3, B = 2.2 M/S^2, C = 1.7m/S And X And T Are In Si Units. What Is The Inst

The position of an object is given by x = at3 - bt2 + ct, where a = 4.1 m/s^3, b = 2.2 m/s^2, c = 1.7m/s and x and t are in SI units. What is the instantaneous acceleration of the object when t=0.7s?

The instantaneous acceleration of the object : 12.82 m/s²

Further explanation  

The velocity of an object at a given t is called Instantaneous velocity  (the derivate of the displacement function)

Can be formulated:  

v(t) = dx(t)/dt  

Whereas the objects acceleration at a certain t is called Instantaneous acceleration  (the derivate of the velocity function/the second derivate of the displacement function)

Can be formulated:  

a(t)=dv(t)/dt  

An equation of motion:

x = at³-bt²+ct

the first derivate :

v = 3at²-2bt+c

the second derivate

a = 6at-2

Input the value :

\tt a=6\times 4.1\times 0.7-2\times 2.2\\\\a=\boxed{\bold{12.82~m/s^2}}

 

Learn more  

uniformly accelerated motion  

brainly.ph/question/2132892  

brainly.ph/question/2088325  

the probe's velocity relative to the earth  

brainly.ph/question/1467317  

Uniformly accelerated motion: the vertical dimension  

brainly.ph/question/2098492  

#LetsStudy  


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